答题完毕，清屏蔽
<P >第一关</P>
<P ><FONT face="Times New Roman">1 </FONT>答：<FONT face="Times New Roman">A</FONT>、<FONT face="Times New Roman">B</FONT>两色块一样亮，因为理论上亮光下的黑块和阴影下的白块亮度等同，在<FONT face="Times New Roman"> Photoshop</FONT>中查的<FONT face="Times New Roman">CMYK</FONT>值都为<FONT face="Times New Roman">58</FONT>、<FONT face="Times New Roman">50</FONT>、<FONT face="Times New Roman">49</FONT>、<FONT face="Times New Roman">17</FONT>因此判断两色块一样亮。</P>
<P ><FONT face="Times New Roman">2 </FONT>答：该图应为曝光欠缺，因为在左手处有明显的红斑出现。</P>
<P ><FONT face="Times New Roman">3 </FONT>答：最亮处于最暗处</P>
<P ><v:shapetype><v:stroke joinstyle="miter"></v:stroke><v:formulas><v:f eqn="if lineDrawn pixelLineWidth 0"></v:f><v:f eqn="sum @0 1 0"></v:f><v:f eqn="sum 0 0 @1"></v:f><v:f eqn="prod @2 1 2"></v:f><v:f eqn="prod @3 21600 pixelWidth"></v:f><v:f eqn="prod @3 21600 pixelHeight"></v:f><v:f eqn="sum @0 0 1"></v:f><v:f eqn="prod @6 1 2"></v:f><v:f eqn="prod @7 21600 pixelWidth"></v:f><v:f eqn="sum @8 21600 0"></v:f><v:f eqn="prod @7 21600 pixelHeight"></v:f><v:f eqn="sum @10 21600 0"></v:f></v:formulas><v:path o:connecttype="rect" gradientshapeok="t" o:extrusionok="f"></v:path><o:lock aspectratio="t" v:ext="edit"></o:lock></v:shapetype><v:shape><v:imagedata></v:imagedata></v:shape></P>
<P >调整曝光</P>
[align=right][color=#000066][此贴子已经被作者于2006-2-12 22:53:21编辑过][/color][/align]
